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The following illustration shows the tensile strength required by each cable cleat dependent upon fixing centres / intervals.
Ft = 0.17 ip2 / S
Ft = maximum force on the cable conductor (N/m)
0.17 (190 x 190) / (36 /1000) = 170,477.22 N/m Cable Ø = 36mm ip = 190kA mounting intervals: 300mm (x 0.3) = 51,141.67N per cable cleat
0.17 (190 x 190) / (36 /1000) = 170,477.22 N/m Cable Ø = 36mm ip = 190kA mounting intervals: 600mm (x 0.6) = 102,283.33N per cable cleat. Therefore each cable cleat in this configuration must restrain two times the force of those in the above configuration (300mm).
0.17 (190 x 190) / (36 /1000) = 170,477.22 N/m Cable Ø = 36mm ip = 190kA mounting intervals: 900mm (x 0.9) = 153,424.00N per cable cleat. Therefore each cable cleat in this configuration must restrain 1.5 times the force of those in the above configuration (600mm), or three times the force of those in the first configuration (300mm).
